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ENTRY LEVEL MATHS
Multiplication and division
General stuff
When you see some groups of same items then multiplying is the
fastest way to calculate the total.How many white pads are there?
One way you could say:there
are two rows by 4 pads
that's 4+4=8
or 2×4=8
Other way you could say:there are four columns by 2 pads
that's
2+2+2+2=8
or 4×2=8
Remember: you can swap the numbers either way round when multiply them
2×4=4×2=8
Practice
tip: download 2 and 3 times table, print it, stick it on the wall and practise each day.
When you feel confident with it, then
move on with next tables:
download 4 and 5 times table;
download 6 and 7
times table;
download 8 and 9 times table.
Practice tasks:
- How many cubes are there?
4 rows by 5 cubes makesOR
5+5+5+5 = 4×5 = ?5 columns by 4 cubes makes
4+4+4+4+4 = 5×4 = ?4×5=20
5×4=20 - How many cubes are there?
How many dots are there?
× = cubes× = dots2×3 = 6 cubes
6×3 = 18 dots - How many 5p coins are there?
How much money is there?
There are 8 coins of 5p
That makes 8×5p = 40p - Write these as multiplication sums:
7+7+7+7+7 = 35
8+8+8 = 24
4+4+4+4 = 16
two tens makes twenty
three fives are fifteen
5×7 = 35
3×8 = 24
4×4 = 16
2×10 = 20
3×5 = 15
-
4×2=9×2=3×2=7×2=2×=10×2=162×=12×2=2
4×2=8 9×2=18 3×2=6 7×2=14 2×5=10 8×2=16 2×6=12 1×2=2 - double five
two lots of two
twice eight
three multiplied by two
double nine
six times two
twice ten
2×2=4
2×8=16
3×2=6
2×9=18
6×2=12
2×10=20
Opposite operations
Practice tasks:
2×4=8
4×2=8
8÷2=4
8÷4=2
3×6=18
6×3=18
18÷3=6
18÷6=3
4×6=24
6×4=24
24÷4=6
24÷6=4
2×5= | 16÷8= |
3×=21 | 45÷=9 |
×4=16 | ÷7=2 |
2×5=10 | 16÷8=2 |
3×7=21 | 45÷5=9 |
4×4=16 | 14÷7=2 |
Multiplication words
Division words
Practice tasks:
- The number 35 is p t of 5 and 7
- The numbers 8 and 9 are f s of 72
- The number 48 is m e of either 6 or 8
- Since 5×7=35, the number 35 is product of 5 and 7
- Since 8×9=72, the numbers 8 and 9 are factors of 72
- Since 6×8=48, the number 48 is multiple of either 6 or 8
Find missing words:
- The number 6 d s 36
- The number 25 is d e by 5
- 24 o r 8 makes 3
- Since 36÷6=6, the number 6 divides 36
- Since 25÷5=5, the number 25 is divisible by 5
- Since 24÷8=3, then we can say 24 over 8 makes 3
Find missing words:
- In the "bus stop" division we write the d d under the "bus stop"
- Q t may include the whole part and the remainder
- 5.27 is a d l number
- In the "bus stop" division we write the dividend under the "bus stop"
- Quotient may include the whole part and the remainder
- 5.27 is a decimal number
The use of times table
You can download your times table here.
Practice tasks:
- 3×6=?
- 4×5=?
- 7×8=?
- 3×6=18
- 4×5=20
- 7×8=56
Find quotient:
- 30÷6=?
- 81÷9=?
- 24÷8=?
- 30÷6=5
- 81÷9=9
- 24÷8=3
Find factor:
- 8×=32
- ×9=27
- 8×4=32
- 3×9=27
Find divisor:
- 63÷=9
- 63÷7=9
Find dividend:
- ÷7=6
- 42÷7=6
Multiplication
Multiplication facts
0 × any number = 0 e.g. 0×0=0, 0×1=0, 0×2=0, 0×3=0, etc.
1 × any number = same number e.g. 1×0=0, 1×1=1, 1×2=2, 1×3=3, etc.
10 × any integer = same number with 0 at the end e.g. 10×1=10, 10×5=50, 10×20=200, 10×37=370, etc.
100 × any integer = same number with 00 at the end e.g. 100×4=400, 100×16=1600, 100×23=2300,
100×60=6000, etc.
1000 × any integer = same number with 000 at the end and so on...
Short multiplication - by a single digit number
Practice tasks:
Long multiplication - by a few digit number
Practice tasks:
Division
Division facts
any number ÷ 0 is undefinedand
therefore not allowed
so NEVER divide by zero
0 ÷ any number = 0 e.g.
0÷1=0, 0÷7=0, 0÷24=0, 0÷158=0, etc.
any number ÷ 1 = same number e.g. 1÷1=1, 8÷1=8,
49÷1=49, 515÷1=515, etc.
any number ÷ same number = 1 e.g. 1÷1=1, 9÷9=1, 36÷36=1,
284÷284=1, etc.
integer that ends with zeros ÷ 10 = cross out last zero e.g. 40÷10=4, 100÷10=10,
170÷10=17, 1050÷10=105, etc.
integer that ends with zeros ÷ 100 = cross out last two zeros e.g.
300÷100=3, 800÷100=8, 1300÷100=13, 21000÷100=210, etc.
and so on...
Short division - by a single digit number
Practice tasks:
basic | medium | harder |
6322÷2= | 1316÷5= | 656÷7= |
636÷3= | 306÷8= | 728÷9= |
6342÷7= | 1367÷4= | 7790÷9= |
basic | medium | harder |
6322÷2 =3161 |
1316÷5 =263 rem 1 =263.2 |
656÷7 =93 rem 5 =93.714... |
636÷3 =212 |
306÷8 =38 rem 2 =38.25 |
728÷9 =80 rem 8 =80.888... |
6342÷7 =906 |
1367÷4 =341 rem 3 =341.75 |
7790÷9 =865 rem 5 =865.555... |
Long division - by a few digit number
Practice tasks:
basic | medium | harder |
3465÷11= | 4863÷15= | 8063÷26= |
8463÷21= | 7189÷14= | 36254÷44= |
basic | medium | harder |
3465÷11 =315 |
4863÷15 =324 rem 3 =324.2 |
8063÷26 =310 rem 3 =310.115... |
8463÷21 =403 |
7189÷14 =513 rem 7 =513.5 |
36254÷44 =823 rem 42 =823.954... |
Level 1 and Level 2
GCSE
A STRAIGHT LINE
A straight line we can represent in coordinate plane by an equation y=mx+c
- x and y are two coordinates of each particular point that belongs to the line
- m is gradient that describes the slope of the line
- c is y-intercept where the line crosses y-axis
From the equation to the graph
Practice tasks:
y = -x + 2
From the points to the equation
Practice tasks:
x | y |
---|---|
8 | -1 |
-4 | 5 |
M(-2,-1) and N(2,3)
belong to the same line.
Work out the equation of the straight line.
Intercepts from the table
Practice tasks:
x | y |
---|---|
-3 | -12 |
-2 | -9 |
-1 | -6 |
(,0)
(1,0)
Simultaneous equations
Task 1: one solution
Tasks 2 and 3: other cases
Correction of the mistakes:
Mistake1 read "different" instead of "diferent";
Mistake2 read "=-2-3/2" instead of "=-2+3/2" and following read "=-7/2" instead of "=-1/2"
Practice tasks:
- 2x+y=9
4x+2y=20
Equations in standard form
y = -2x+9
y = -2x+10
Lines are parallel. There are no solutions. - 3x-y=12
6y=18x-72
Equations in standard form
y = 3x-12
y = 3x-12
Lines match each other. There are infinite amount of solutions - all along the line. - 4x+2y=10
2x-2y=14
Equations in standard form
y = -2x+5
y = x-7
There is one solution
x = 4 and y = -3
OR
point (4,-3) - What are essential requirements to determine the amount of solutions for linear simultaneous equations?
a) exactly one solution;
b) no solutions;
c) infinitely many solutions?
In standard form y=mx+c there should be:
a) different coefficient m next to x;
b) same coefficient m but different number c;
c) same coefficient m and same number c. - If one of the lines is y= -75x+57 then what is possible equation for another line to have:
a) exactly one solution;
b) no solutions;
c) infinitely many solutions?
The other line have to come in standard form y=mx+c to:
a) different coefficient m next to x and no matter of c,
e.g. y= -5x+57 or y= -5x+5 or y= 75x+57;
b) same coefficient m but different number c,
e.g. y= -75x+50 or y= -75x-57;
c) same coefficient m and same number c, so the only option is y= -75x+57